A yacht is moving at 10 km/h in a south-easterly direction. It encounters a 3 km/h current from the north.
Find the resultant speed and direction.
Answers
Answered by
0
Answer:
Step-by-step explanation:
I made a sketch and it looks like a simple cosine law problem
d^2 = 10^2 + 3^2 - 2(10)(3)cos135
= 151.426...
d = 12.3 km/hr
then to find the small acute angle Ø
sinØ/3 = sin 135°/12.3..
sinØ = .1723..
Ø = 9.927°
direction is S (45-9.927..)° E
= S 35° E to the nearest degree
Similar questions