Question

A year ago, a person's age was 8 times the age of his son.
If his age at present is equal to his son's age class, theirs
See current age.​

Answer 1

Answer:

Let the present age of the son be x years

present age of man = x² years

One year ago sons age,

sons age = ( x-1) years

Father's age=( x²-1) years

It is given that eight hence, the age of father will be three times the age of son

2x²+ 8=3(x+8)+4

2x² + 8= 3x+24+4

2x²- 3x-20=0

2x²+8x+5x-20=0

2x²(x-4)+5(x-4)=0

(x-4) (2x+5)=0

x=4,-5/2

But the age cannot be in negative so the age is x=4

present age of son=4 years

present age of father=2(4)² years= 32 years.

Step-by-step explanation:

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