Math, asked by JayTarpara6707, 1 year ago

A year ago the father 8times as ols as his son.Now his age is the square of his age.find their present age

Answers

Answered by arju786
1

Answer:

Father's age- 49 yrs and son's age- 7 yrs

Step-by-step explanation:

Let father's age be x and that of son be y.

Now according to the question,

x-1 = 8(y-1)

x-1 = 8y-8

x-8y = -7

Also given,

x = y^2

then,

y^2-8y = -7

y^2-8y+7 = 0

y^2-y-7y+7 = 0

By solving, we get,

y = 1 or y = 7

Now y = 1 is not possible.

Then,

y = 7, and so,

x-8y = -7

so, x-8×7 = -7

x-56 = -7

X = 49

THEREFORE, YOUR ANSWER IS,

Father's age = 49 yrs

Son's age = 7 yrs

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