Math, asked by yashaugust3111, 1 year ago

A year ago, the father's age was 8 times his son's age. His present age is square of his son's age. Find their present ages.

Answers

Answered by shivani5207

0

father age =X

son age=8x

before a year ,,,

now, Thier present ages are,,,,

father age =x+1=4(8X+1)

son age=8x+1=8x+1

Answered by imranali20030666

0

Answer:

Step-by-step explanation:

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