Question

a yellow substance is photosensitive in exposure to sunlight it gives greenish substance Y and brown fumes Z.
identify X,Y,Z?
how will you obtain X from nitrate salt of Y?
plz answer fast its urgent

Answer 1

Hi friend,

Your answers are

Evolution of brown fumes of a gas on exposure to sunlight suggests, that the gas (Z) is Br2 and X must be the bromide salt of Y. Now, AgBr is the salt that decomposes on exposure to sunlight, into Ag (greyish coloured substance) and Br2 gas.

Ag(s) +Br2 --hv------->Agbr(s)

Therefore, X is AgBr and Y is Ag(s).

Now, AgBr can be obtained from AgNO3, by reacting it with KBr, where K displaces Ag from AgNO3 and Br displaces NO3 from AgNO3, as per the following reaction:

AgNO3 + KBr → AgBr + KNO3

Thus, X = AgBr

Y = Ag

Z = Br2.

Hope this helps you..☺☺