Question

A young girl lost a diamond . The father brought her another one that costs $23,961 more than the previous one . if the father brought the diamond for 1,69,000 what was the price of the diamond that was lost ??​

Answer 1

Answer:

$83304.50

Step-by-step explanation:

$let \: the \: previous \: diamond's \: pice \: be \: x \: \\ then ,\: the \: new \: diamond's \: price \: is \: (x + 2391) \\ under \: the \: terms , \\ x + (x + 2391) = 169000 \\ x + x + 2391 = 169000 \\ 2x = 169000 - 2391 \\ 2x = 166609 \\. '. \: x = 83304.50 \\ \\ .'. \: the \: previous \: diamond 's\: price \: is \: 83304.50$

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