Math, asked by Innu9552, 8 months ago

A young sumo wrestler decided to go on a special diet to gain weight rapidly.
WWW represents the wrestler's weight (in kilograms) after t months.
W=80+5.4tW=80+5.4tW, equals, 80, plus, 5, point, 4, t
What was the wrestler's weight before his special diet?

Answers

Answered by AditiHegde
18

Given:

A young sumo wrestler decided to go on a special diet to gain weight rapidly.

W represents the wrestler's weight (in kilograms) after t months.

W = 80 + 5.4t

To find:

What was the wrestler's weight before his special diet?

Solution:

From given, we have,

W = 80 + 5.4t

where W represents the wrestler's weight (in kilograms) after t months.

So, from the given equation, it's clear that young wrestler's weight after t months is 80 + 5.4t.

When we substitute t = 0, we will get the weight of that young wrestler before his special diet.

Therefore, we have,

W = 80 + 5.4 (0)

W = 80 + 0

W = 80 kg.

Hence, 80 kg was the weight of young sumo wrestler before his special diet.

Answered by Walterduck21
1

Answer:

80 kg

Step-by-step explanation:

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