A yower of height h covers distance of h/2 in last second . then find the height of tower
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The distance covered by the ball in n th second is given by,
S n = u + ½a(2n - 1)
=> h/2 = 0 + ½ × g × (2n - 1)
=> 2n – 1 = h/g
=> n = ½ (h/g + 1)
So, the ball remains in air for time ½ (h/g + 1).
S n = u + ½a(2n - 1)
=> h/2 = 0 + ½ × g × (2n - 1)
=> 2n – 1 = h/g
=> n = ½ (h/g + 1)
So, the ball remains in air for time ½ (h/g + 1).
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