A Zener diode is specified having a breakdown voltage of 9.1 V with a maximum power dissipation of
364 mW. What is the maximum current that the diode can handle?
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P=VI
364mW=9.1 × I
I = 364÷9.1 ma
I= 40mA
364mW=9.1 × I
I = 364÷9.1 ma
I= 40mA
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