Question

A zero of a polynomial p(x)=(x-3) (x-2) is

Answer 1

Answer:

to find zeroes,

p(x) = 0

=> (x -3)( x -2) = 0

=> x -3 = 0 , or x -2 = 0

=> x = 3 or, x -2 = 0

=> x = 3 or , x = 2

so, the zeroes of p(x) are 3 and 2.

Answer 2

Answer:

$zeros \: of \: polynomial \\ \\ \\ p(x) = (x - 3)(x - 2) \\ \\ \\ \implies \: x - 3 = 0 \: x - 2 = 0 \\ \\ \\ \implies \: x = 3,x = 2 \\ \\ \\ so \: zeros \: of \: polynomial \: p(x) = 3 \: and \: 2$