Question

A zero of x3 +64 is:​

Answer 1

Answer:

${x}^{3} + 64 = 0 \\ {x}^{3} = - 64 \\ x = \sqrt[3]{ - 64} \\ x = \sqrt[3]{ ( - 2) \times ( - 2) \times ( - 2)} \\ x = - 2$

So , The zero of this Polynomial is -2