Question

A zero of x3(x cube) + 64 is
(a) 0 (b) 4 (c) 4i (d) -4​

Answer 1

Answer:

(d) 64

Step-by-step explanation:

x³+64=0

x³=-64

x=-✓64

x=-4

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Answer 2

Answer:

zero of the equation $x^{3} +64$ is -4

Step-by-step explanation:

Given equation might be $x^{ 3} + 64$

Zero of a equation is a value which gives 0 on substituting in place of variable  

⇒   $x^{3} + 64 =0$

⇒ $x^{3} =-64$  

⇒ $x = - \sqrt[3]{64}$

⇒ x = $-\sqrt[ 3]{ 4^{3} }$

⇒ x = -4   therefore correct answer is -4

here we can check by substituting  4 in x place

$x^{3} + 64$  ⇒  $(-4)^{3}$  + 64  =  -64 + 64 =0

the zero of the given equation is -4