Chemistry, asked by bunny1651, 1 year ago

A zinc plate was put into a solution of copper sulphate kept in a glass container. It was
found that blue colour of the solution gets fader and fader with the passage of time.
After a few days when zinc plate was taken out of the solution, a number of holes were
observed on it.
(a) State the reason for changes observed on the zinc plate.
(b) Write the chemical equation for the reaction involved.​

Answers

Answered by Anonymous
31

\huge\text{\underline{Answer}}

When the zinc metal is put in to the solution it displaces the copper from sulphate solution and the blue copper get faded.

Reason :-

Since, zinc is more reactive than copper so it displaces it from sulphate solution and form zinc sulphate which is white in colour.

The zinc plate has formed several holes because the zinc get react with sulphate solution and by the passage of time all the zinc metal reacts with copper sulphate solution by forming tiny holes in to the zinc metal.

Ans:-2

This is a displacement reaction can be written as :-

\bold{Zn + CuSO4 => ZnSO4 + Cu }

here, copper is displaced by zinc and it get collected either in bottom or deposited in zinc plate.

Answered by Anonymous
4

Answer:(1) Zinc is more reactive than copper. It displaces cu from cuso4 and hence copper gets deposited on the zinc plate

(2) This is a displacement reaction

Zn+Cuso4--ZnSo4+cu

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