a zinc plate was put into a solution of copper sulphate kept in a glass container. It was found that blue colour of solution gets fader and fader with the passage of time. After few days when zinc plate was taken out of solution, a number of holes were observed on it. 1) state the reason for the change observed on the zinc plate. 2) write the chemical equation for the reaction involved.
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1) The reason for the holes is that the zinc reacts with copper sulphate to form zinc sulphate, a colorless solution, and the displaced copper settles down as precipitate. So, the zinc plate gets holes in it from where the zinc ions leave to combine with the sulphate ions.
2) Zn(s) +CuSO4(aq) =====Cu(s) +ZnSO4(aq)
2) Zn(s) +CuSO4(aq) =====Cu(s) +ZnSO4(aq)
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Answer:
A Zinc plate, when put in a solution of Copper Sulphate will decolorize the blue colour of the Copper sulphate solution.
1) This is because Zinc is more reactive than Copper and replaces copper in copper sulphate solution.
2) The chemical equation for reaction is:
Zn + CuSO₄ → ZnSO₄ + Cu
Explanation:
- The reactivity series as shown in the image gives the reactivity of the different elements. We can see that Zinc is much more reactive as compared to Copper. So it will have greater ability to lose electrons and form positive ions.
- The metal which is more reactive can replace the less reactive metal from its salt. Zinc, being more reactive will be able to replace Copper from its salt i.e. Copper sulphate.
- The chemical equation for reaction is: Zn + CuSO₄ → ZnSO₄ + Cu
- This will decolorize blue color of Copper sulphate solution and also holes will be observed on the Zinc plate.
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