Question

A zirconium 4oZr100 nucleus, is a ß-emitter.
The product nucleus is also a B - emitter.
What is the final resulting nucleus of these
two decays?
100 Sr 38
100 M0 42
98 Zr 40
102 Zr 40
​

Answer 1

Answer:

Molybdenum (100 Mo 42 )

Explanation:

Refer attachment for explanation!!!