Question

A zookeeper was asked how many camel's and ostriches there were in the zoo. The zookeeper said,"among the animals there are 60 eyes and 86 feet"

Answer 1

Answer:

c 13

O 17

Step-by-step explanation:

eyes

2c+2o=60 c+o=30

legs

4c+2o=86 2c+o=43

c 13

o=17

Answer 2

Camels = 13

Ostrich = 17

Given:

among the animals there are 60 eyes and 86 feet

To find:

Number of camels and ostriches

Solution:

An ostrich has 2 legs and camel has 4 legs and both the animals have 2 eyes each.

Let the camels be x and ostrich be y

So there are thirty eyes in total

Eyes of one camel = 2

So total camel eyes = Number of camel * eyes of camel = x*2 = 2x

Eyes of one ostrich = 2

So total ostrich eyes = Number of ostrich * eyes of ostrich = y*2 = 2y

Total eyes = eyes of camel + eyes of ostrich

60 = 2x + 2y

60 = 2(x+y)

60/2 = x+y

x + y = 30

y = 30-x

Now legs of one camel = 4

So, legs of all camel = number of camel * legs of each camel = x*4 = 4x

Legs of ostrich = 2

Legs of all ostrich = Number of ostrich * Legs of each ostrich = y * 2 = 2y

Legs of ostrich + legs of camel = total legs

2y + 4x = 86

2(y+2x) = 86

y + 2x = 86/2

y + 2x = 43

Putting value of y in equation

30-x+2x = 43

x = 43-30 = 13

y = 30-x = 30-13 = 17

Camels = x = 13

Ostrich = y = 17

Hence, there are 13 camels ad 17 ostrich in the zoo.

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