A zum of money placed at ci doubles itself in 4 years .It will amount to eight times in ?
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Let,Principal=Rs.100
Amount=Rs.200
Rate=r%
Time=4years
Now,
A=P×[1+(r100)]n200=100×[1+(r100)]42=[1+(r100)]4−−−−−−(i)
If sum become 8 times in the time in years then,
8=(1+(r100))n23=(1+(r100))n−−−−−−(ii)
Usingeqn(i)in(ii),
weget([1+(r100)]4)3=(1+(r100))n[1+(r100)]12=(1+(r100))n
Thus,n=12years.
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