Chemistry, asked by eshapaul, 2 months ago

A°mAlCl3 (in Scm2 mol-1) is equal to
(Given,
A°m(Al(OH)3)
= x Scm? mol-1
A°mHcl) = y Scm2 mol-1
A°m(H2O)
= Z Scmmol-1
Here A°m -> limiting molar conductivity]
(1) x + 3y – Z
(2) x + 3y - 32
3) x + y - 32
(4) x - 3y + 32​

Answers

Answered by alamdarwesh9123
0

Answer:

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