Question

a1 = 2a0 + 1 a2 = 2a1 + 1 = 2(2a0 + 1) + 1 = 22 a0 + 2 + 1 a3 = 2a2 + 1 = 2(22 a0 + 2 + 1) + 1 = 23 a0 + 22 + 2 + 1 a4 = 2a3 + 1 = 2(23 a0 + 22 + 2 + 1) + 1 = 24 a0 + 23 + 22 + 2 + 1 . . . an = 2n a0 + 2n−1 + 2n−2 + · · · + 2 + 1 = 2n a0 + 2n − 1.

Answer 1

Answer:

0

i am not sure but i think it's answer is 0.

hope this helps you

Answer 2

Answer:

mark me as brainlist please