a1=4,an+1=2nan , find first six term of each of following sequence
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Answer:
1, 8, 32, 192, 1536, 15360
Step-by-step explanation:
aₙ₊₁ = 2naₙ (given)
Now, a₁ = 4 so
When n = 1, aₙ₊₁ = a₁₊₁ = a₂ = 2(1)(a₁) = 2(1)(4) = 8
When n = 2, aₙ₊₁ = a₂₊₁ = a₃ = 2(1)(a₂) = 2(2)(8) = 32
When n = 3, aₙ₊₁ = a₃₊₁ = a₄ = 2(3)(a₃) = 2(3)(32) = 192
When n = 4, aₙ₊₁ = a₄₊₁ = a₅ = 2(4)(a₄) = 2(4)(192) = 1536
When n = 5, aₙ₊₁ = a₅₊₁ = a₆ = 2(5)(a₅) = 2(5)(1536) = 15360
When n = 6, aₙ₊₁ = a₆₊₁ = a₇ = 2(6)(a₆) = 2(6)(15360) = 184320
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