Math, asked by vivekgupta8498, 5 hours ago

a1=4,an+1=2nan , find first six term of each of following sequence​

Answers

Answered by JessicaRoyale1
0

Answer:

1, 8, 32, 192, 1536, 15360

Step-by-step explanation:

aₙ₊₁ = 2naₙ (given)

Now, a₁ = 4 so

When n = 1, aₙ₊₁ = a₁₊₁ = a₂ = 2(1)(a₁) = 2(1)(4) = 8

When n = 2, aₙ₊₁ = a₂₊₁ = a₃ = 2(1)(a₂) = 2(2)(8) = 32

When n = 3, aₙ₊₁ = a₃₊₁ = a₄ = 2(3)(a₃) = 2(3)(32) = 192

When n = 4, aₙ₊₁ = a₄₊₁ = a₅ = 2(4)(a₄) = 2(4)(192) = 1536

When n = 5, aₙ₊₁ = a₅₊₁ = a₆ = 2(5)(a₅) = 2(5)(1536) = 15360

When n = 6, aₙ₊₁ = a₆₊₁ = a₇ = 2(6)(a₆) = 2(6)(15360) = 184320

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