Question

A1, A2, A3, A4, A5 are the 5 A.M's inserted between 10
and 100 then A4=
1) 70
2) 80
3) 90
4) 60
​

Answer 1

Answer:

Initial term (a)=10

Final term (l)=28

11 AM's are inserted between 10 & 28

∴ therefore are 13 terms in sequence

last term (13

th

term) = 10+(13−1)d

10+12d=28

12d=18;d=1.5

Therefore the series will be

a,a+d,a+2d,a+3d,a+4d,a+5d,a+6d,a+7d,a+8d,a+9d,a+10,a+11d,a+12d

10,11.5,13,14.5,16,17.5,19,20.5,22,23.5,25,26.5,28

Therefore there are 5 integral AM's

Step-by-step explanation:

hope it helps you...

Answer 2

Answer:

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