A1, A2, A3, A4, A5 are the 5 A.M's inserted between 10
and 100 then A4=
1) 70
2) 80
3) 90
4) 60
Answers
Answered by
4
Answer:
Initial term (a)=10
Final term (l)=28
11 AM's are inserted between 10 & 28
∴ therefore are 13 terms in sequence
last term (13
th
term) = 10+(13−1)d
10+12d=28
12d=18;d=1.5
Therefore the series will be
a,a+d,a+2d,a+3d,a+4d,a+5d,a+6d,a+7d,a+8d,a+9d,a+10,a+11d,a+12d
10,11.5,13,14.5,16,17.5,19,20.5,22,23.5,25,26.5,28
Therefore there are 5 integral AM's
Step-by-step explanation:
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Answered by
3
Answer:
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