a1+a2+a3+...+a50 =50 then the minimum value of 1/a1+1/a2+1/a3+...+1/a50 is
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a
1
.a
2
.a
3
...a
n
=1
Hence, a
i
n
=1
Since a
i
is Real, therefore a
i
=1
Hence, (1+a
1
+a
1
2
)(1+a
2
+a
2
2
)...(1+a
n
+a
n
2
)
=(1+a
i
+a
i
2
)
n
=3
n
.
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