A100 watt bulb emit a monophrotic light 400nm . Find the number of photon emitted in hertz by the bulb
Answers
Answer:
Hey dear,
● Answer -
N = 2×10^20 photons
● Explanation -
Energy of isolated photon is calculated by -
E = hc/λ
E = (6.63×10^-34 × 3×10^8) / (4×10^-7)
E = 4.97×10^-19 J
No of photons emitted per unit time is calculated by -
N = P / E
N = 100 / (4.97×10^-19 J)
N = 2×10^20 photons
Therefore, 2×10^20 photons are emitted.
Explanation:
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CHEMISTRY
A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb.
November 22, 2019avatar
Shaifali Razvi
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VIDEO EXPLANATION
ANSWER
Power of the bulb = 100 watt = 100Js
−1
Energy of one photon is E=hν=hc/λ
where, h=6.626×10
−34
Js,c=3×10
8
ms
−1
Given λ=400nm=400×10
−9
m
By putting the values, we get
E=6.626×10
−34
×3×10
8
/(400×10
−9
)
E=4.969×10
−19
J
Number of photons emitted in 1 sec × energy of one photon = power
n×4.969×10
−19
=100
n=
4.969×10
−19
100
n=2.012×10
20
photons per sec
So, option C is correct