Question

A100watt bulb emits light of wavelength 6000 Angastrom. find the no.photons emitted by bulb per mintue​

Answer 1

Answer:1.81×10^22

Explanation:

See,the formula for power is

Power=Energy/time

So,100Waat×60secs (cause time is one mint)

And=6000J.

Now,energy of photon is

Energy of photon=nhc/wavelength...where n is no. of photons,h is planks constant of value 6.625X10^-34Js and c is speed of light i.e 3x10^8m/s

So by placing the values in formula

n=E×wavelength/hxc...where E is energy found through power formula i.e 6000J

So,6000x6000x10^-10/6.625x10^-34x3x10^8

Ans is 1.81x10^22