Question

a12=37,d=3,find a and S12 in short

Answer 1

given n=12
an=37
d=3
so an = a + (n-1)d
37=a+(12-1)3
37=a+33
37-33=a
so a = 4
so s12 = n/2(a+an)
s12=12/2(4+37)
s12=6×41
s12 =246

Answer 2

Answer:

Step-by-step explanation:

given a¹² = 37

d= 3

so n = 12

now

a¹³ = a + (12-1)(3)

a¹³ = a + 33

37 = a + 33

so a = 4

now sⁿ = n/2(a+aⁿ)

s¹² = 6(41)

=> 246