a¹²x⁴ - a⁴x¹² factorize
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(ax)^4(a^8-x^8)
hope helps
hope helps
Answered by
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a^12x4 - a^4x^12
= a^4 x^4 ( a^8 - x^8 )
= a^4 x^4 (a^4 + x^4 ) ( a^4 - x^4) [ as (a^2 - b^2) = (a+b) ( a-b)]
= a^4 x^4 (a^4 + x^4 ) (a^2 + x^2 ) (a^2 - x^2)
= a^4 x^4 (a^4 + x^4) ( a^2 + x^2) (a+x) (a-x)
So the factorizd form is
a^4x^4 (a^4 + x ^4) (a^2+ x^2) (a+x ) (a-x)
Hope it helps.
= a^4 x^4 ( a^8 - x^8 )
= a^4 x^4 (a^4 + x^4 ) ( a^4 - x^4) [ as (a^2 - b^2) = (a+b) ( a-b)]
= a^4 x^4 (a^4 + x^4 ) (a^2 + x^2 ) (a^2 - x^2)
= a^4 x^4 (a^4 + x^4) ( a^2 + x^2) (a+x) (a-x)
So the factorizd form is
a^4x^4 (a^4 + x ^4) (a^2+ x^2) (a+x ) (a-x)
Hope it helps.
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