Question

A15 m long ladder reached a window 12 m
05
high from the ground on placing it against a
wall at a distance a. Find the distance of the
foot of the ladder from the wall.
12 cm
15 cm​

Answer 1

according to pythagoras theorem h^2= p^2 + b^2

15^2=12^2+b^2

225=144+b^2

225-144=b^2

81=b^2

81^1/2=b

9=b

distance of ladder from wall =9cm

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Answer 2

Answer:

Let AC be the ladder and A be the window.

Given: AC=15m, AB=12m, CB=am

In right angled triangle ACB,

(Hypotenuse)²=(Base)²+[Perpendicular)²

[By Pythagoras theorem]

⇒(AC)²=(CB)²+(AB)²

⇒(15)²=(a)²+(12)²

⇒225=a²+144

⇒a² =225−144=81

⇒a= 81

a=9cm

Thus, the distance of the foot of the ladder from the wall is 9m.

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