A1B = 3,B2B=0,C1B=5,,D2A=3,E1C=?
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Given : A1B = 3,B2B=0,C1B=5,,D2A=3
To find : E1C
Solution:
We will use here
A = 1 B = 2 C = 3 D = 4 ............. Z = 26
A1B = 1 + 2 = 3
here A = 1 , B = 2 & 1 = +
B2B = 2 - 2 = 0
Here B = 2 & 2 = -
C1B = 3 + 2 = 5
Here C = 3 B = 2 & 1 = +
D2A = 4 - 1 = 3
D = 4 , A = 1 & 2 = -
E1C
= 5 + 3 = 8
E1C = 8
Logic 1 Stands for addition & 2 Stands for subtraction
A , B , C takes values as per their position in alohabated
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