a2+1/a2=18 find the value of a a+1/a and a-1/a
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Answered by
2
In the above Question , the following information is given -
a² + 1 / a² = 18
To find -
[ A ] a + 1 / a
[ B ] a - 1 / a
Solution -
[ A ]
a² + 1 / a² = 18
=> a² + 1 / a² - 2 = 18 - 2
= > a² + 1 / a² - 2 = 16
=> ( a - 1 / a ) ² = 4²
=> ( a - 1 / a ) = 4
[ B ]
a² + 1 / a² = 18
=> a² + 1 / a² + 2 = 18 + 2
=> a² + 1 / a² + 2 = 20
=> ( a + 1 / a ) ² = 20
=> ( a + 1 / a ) = √ { 20 }
=> ( a + 1 / a ) = √ { 4 × 5 }
=> ( a + 1 / a ) = √ { 2² × 5 }
=> ( a + 1 / a ) = 2 √ 5
________________
Answer -
Hence the required answer Becomes -
[ A ] ( a - 1 / a ) = 4
[ B ] ( a + 1 / a ) = 2 √ 5
________$
Answered by
2
Step-by-step explanation:
HI DEAR,
a²+1/a² =18
(a+1/a)²= a²+1/a²+2
a+1/a = √20 = 2√5
(a²+1)/a= 2√5
a²+1-2√5a=0
a = √5±2
HOPE IT HELPS...
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