Question

a²+1/a²+2-3a-3/a factorise the following​

Answer 1

Answer:

a²+1/a²-2-3a+3/a

= (a-1/a)²-3(a-1/a)

Take (a-1/a) as common factor.

= (a-1/a) {(a-1/a)-3)

= (a-1/a) (a-1/a-3).

This is the answer.

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Answer 2

a²+1/a²-2-3a+3/a

= (a-1/a)²-3(a-1/a)

Take (a-1/a) as common factor.

= (a-1/a) {(a-1/a)-3)

= (a-1/a) (a-1/a-3).