a²+1/a²=23 find a³+1/a³
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Solution:
» a² + 1/a² = 23 ... (1)
» a² + 1/a² + 2 = 25
» a + 1/a = 5 ... (2)
Now, a³ + 1/a³ = (a + 1/a) [a² - a (1/a) + 1/a²]
from (1) & (2)
=> a³ + 1/a³ = (5) (23 - 1)
» a³ + 1/a³ = 5 (22) = 110
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