Question

A² + 1/a² = 27
a - 1/a = ?

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Answer 1

Answer:

♧ ᴀɴsᴡᴇʀ♧

Given that,

A² + 1/a² = 27

so, (A)² + (1/a)² - 2a.1/a = 27a.1/a

=> (a - 1/a)² = 27-2

=> a - 1/a = √25

=> a - 1/a = 5

Hence, a - 1/a = 5 .

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Answer 2

Answer:

Given:-

$</p><p>a²+\dfrac{1}{a²}a²+a²1</p><p>$

To Find:-

$a+\dfrac{1}{a}a+a1</strong></p><p><strong>[tex]a+\dfrac{1}{a}a+a1$

Identity used:-

( a -b )² = a² + b² - 2ab

Solution:-

Comparing the given terms with this identity.

So,

$⇒ ( a+\dfrac{1}{a}a+a1 )² = a²+\dfrac{1}{a²}-2a²+a²1−2</p><p>⇒ ( a+\dfrac{1}{a}a+a1 )² = 27 - 2</p><p>⇒ ( a+\dfrac{1}{a}a+a1 )² = 25</p><p>⇒ a+\dfrac{1}{a}a+a1 = √25</p><p>⇒ a+\dfrac{1}{a}a+a1 = ±5</p><p>We will ignore negative term.$

Hence, the value of a+\dfrac{1}{a}a+a1 is +5.