(a²-1)(b²-1)+4ab factorise using difference of two squares method . Plz give right answer and if u type something nonsense i will report ur answer
Answers
Answered by
0
Answer:
that is equal to
a²b² - a² - b² + 1 +4ab
= (a²b² + 2ab + 1) - (a² + b² - 2ab)
= (ab + 1)² - (a - b)²
= (ab + a - b + 1)(ab - a + b + 1)
Hope this helps
Answered by
1
Answer:
a²b² - a² - b² + 1 + 4ab
= [(ab)² + 2. ab. 1 + (1)²] - a² - b² + 2ab
= (ab + 1)² - (a²+b²-2ab)
= (ab + 1)² - (a - b)²
= (ab + 1 - a + b) (ab + 1 + a - b)
Mark me brainliest please.
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