a² + 10a + 25 (factorise)
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−10a+25
=a
2
−5a−5a+25, split middle term so that resultant is same
=(a
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−5a)+(−5a+25), group pair of terms
=a(a−5)−5(a−5), factor each binomials
=(a−5)(a−5), factor out common factor (a−5)
=(a−5)
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Aliter, use (a−b
2
)=a
2
−2ab+b
2
⇒a
2
−10a+25=a
2
−2×5x+5
2
=(a−5)
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