Math, asked by leen69, 7 months ago

a² + 10a + 25 (factorise)​


kavvin0907: a
2
−10a+25
=a
2
−5a−5a+25, split middle term so that resultant is same
=(a
2
−5a)+(−5a+25), group pair of terms
=a(a−5)−5(a−5), factor each binomials
=(a−5)(a−5), factor out common factor (a−5)
=(a−5)
2


Aliter, use (a−b
2
)=a
2
−2ab+b
2

⇒a
2
−10a+25=a
2
−2×5x+5
2
=(a−5)
2

Answers

Answered by Anonymous
7

\huge\underline{\overline{\mid{\bold{\red{☨ AnsweR ☨}}\mid}}}

 {a}^{2}  + 10 a + 25 \\  \\  =  {a}^{2}  + (5 + 5)a + 25 \\  \\  =  {a}^{2}  + 5a + 5a + 25 \\  \\  = a(a + 5) + 5(a + 5) \\  \\  = (a + 5)(a + 5)

\sf\colorbox{blue}{✯ mark - me - as - brainliest ✯}

Similar questions