a2+12a/35+1/35
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(7a+1)(5a+1)/35 will be the answer
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Answered by
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a²+12a/35+1/35
a²+12a+1/35
By using quadratic eq.
ax²+bx+c=0
Therefore
→35a²+12a+1/35=0
→35a²+7a+5a+1=0×35
→7a(5a+1)+1(5a+1)=0
→(7a+1)(5a+1)=0
→7a+1=0;a=-1/7
5a+1=0;a=-1/5
{a=-1/7,-1/5}
____×____
Hope The answer is Correct.
Thank You‼
a²+12a+1/35
By using quadratic eq.
ax²+bx+c=0
Therefore
→35a²+12a+1/35=0
→35a²+7a+5a+1=0×35
→7a(5a+1)+1(5a+1)=0
→(7a+1)(5a+1)=0
→7a+1=0;a=-1/7
5a+1=0;a=-1/5
{a=-1/7,-1/5}
____×____
Hope The answer is Correct.
Thank You‼
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