a² - 22a + 117 factorise it
Answers
Answer:
The first term is, x2 its coefficient is 1 .
The middle term is, -22x its coefficient is -22 .
The last term, "the constant", is +117
Step-1 : Multiply the coefficient of the first term by the constant 1 • 117 = 117
Step-2 : Find two factors of 117 whose sum equals the coefficient of the middle term, which is -22 .
-117 + -1 = -118
-39 + -3 = -42
-13 + -9 = -22 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -13 and -9
x2 - 13x - 9x - 117
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-13)
Add up the last 2 terms, pulling out common factors :
9 • (x-13)
Step-5 : Add up the four terms of step 4 :
(x-9) • (x-13)
Which is the desired factorization
Final result :
(x - 9) • (x - 13)
Step-by-step explanation:
a$-13a+9a+117
a. (a-13)+9( a-13). (a-9) (a-13