Question

a²+2a+2, 3a²+6a+6, 4a²+5a+4 are in A.P, find out the value of a​

Answer 1

Answer:

3a^2+6a+6-(a^2+2a+2) =4a^2+5a+4-(3a^2+6a+6)

3a^2+6a+6-a^2-2a-2=4a^2+5a+4-3a^2-6a-6

2a^2+4a+4=a^2-a-2

a^2+5a+6=0

a^2+3a+2a+6=0

a(a+3) +2(a+3) =0

(a+2) (a+3) =0

a+2=0

a=-2

a+3=0

a=-3

a=-2 and a=-3