Question

a²+ 2ab + b2 ÷a + b​

Answer 1

${a}^{2} + 2ab + {b}^{2} \div a + b \\ \frac{ {a}^{2} + 2ab + {b}^{2} }{a + b} \\ {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ substituting \: this \: identity \: we \: get \\ \frac{{(a + b)}^{2} }{a + b} \: \: \: \: \: \: \: \: \: \: \\ = \frac{(a + b)(a + b)}{(a + b)} \\ we \: will \: cancel \: one \: (a + b) \: from \: numerator \: and \: denominator \\ = (a + b) \\ hope \: this \: helps \: you..... \\ follow \: me \: ❤$

Answer 2

${a}^{2} + 2ab + {b}^{2} \div a + b$

$\green{(a + b) {}^{2} = {a}^{2} +2ab+ {b}^{2} }$

${a}^{2} + 2ab + {b}^{2} \div a + b$

(a+b) (a+b) /(a+b)

=> a + b

$\mathcal\orange{Please\:mark\:as\:brainliest.....}$