Question

a²-2ab+b²-c² Factorize​

Answer 1

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a² + 2ab - c² + b²

=> a² + 2ab + b² - c²

by Identity :-

a² + 2ab + b² = (a + b)²

=> (a + b)² - c²

=> [ (a + b) + c ] [ (a + b) - c ]

Hope it will help!

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Answer 2

Answer:

(a+b+c)(a+b-c)

Step-by-step explanation:

a²-2ab+b²-c²

=(a²+b²-2ab)-c²

=(a+b)²-c²

[∴ We know a²-b²=(a+b)(a-b).Taking a as a+b and b as c, we get:]

(a+b+c)(a+b-c)