a2+2ac-b2+c2 factorise
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4
a2+2ac-b2+c2=a×a+a×c-b×b+c×c
=a (a+c)-(b+c)(b+c)
=a (a+c)-(b+c)(b+c)
Jenna10:
are there no identities associated with it?
Answered by
6
Sorry if I am late but here is the answer
a² + 2ac - b² + c²
= (a² + c² + 2ac) - b²
= (a + c)² - (b)²
= (a + b + c) (a - b + c)
There you go, hope it helps :D
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