Question

a2-4a-1=0 then find the value of a2+1/a2+3a-3/a=?​

Answer 1

Answer:

26

Step-by-step explanation:

A2-4A-1=0

DIVIDE BY "A"

A2/A -4A/A-1/A=0

A-4-1/A=0

A-1/A=4

SQUA BOTH SIDES

A2+1/A2-2=16

A2+1/A2=14

A2+1/A2+3(A-1/A)

14+3(4)

26