Math, asked by nissa8666, 1 year ago

a2-4a+2a+b2-2bc+2c2+5=0


arnab2261: please clear your question,.
arnab2261: ask it clearly,.

Answers

Answered by sinunajla
1

Answer:


Step-by-step explanation:

A = 1, B = 4, C = (b�+2b+5)

Discriminant = B�-4AC = 4�-4(1)(b�+2b+5) = 16-4(b�+2b+5) =  

16-4b�-8b-20 = -4b�-8b-4 = -4(b�+2b+1) = -4(b+1)�

This must not be negative, so the only value it can take on

so that -4(b+1)� is not negative is when it is zero.

which is when b+1=0 or b=-1, so b can only be -1.  So b=-1.

That makes the original equation:

a� + b� + 2b + 4a + 5 = 0

become

a� + (-1)� + 2(-1) + 4a + 5 = 0

       a� + 1 - 2 + 4a + 5 = 0

               a� + 4a + 4 = 0

                    (a+2)� = 0

                       a+2 = 0

                         a = -2

So since a=-2 and b=-1

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nissa8666: Answer is 2
sinunajla: ya
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