a2-4a+2a+b2-2bc+2c2+5=0
arnab2261:
please clear your question,.
Answers
Answered by
1
Answer:
Step-by-step explanation:
A = 1, B = 4, C = (b�+2b+5)
Discriminant = B�-4AC = 4�-4(1)(b�+2b+5) = 16-4(b�+2b+5) =
16-4b�-8b-20 = -4b�-8b-4 = -4(b�+2b+1) = -4(b+1)�
This must not be negative, so the only value it can take on
so that -4(b+1)� is not negative is when it is zero.
which is when b+1=0 or b=-1, so b can only be -1. So b=-1.
That makes the original equation:
a� + b� + 2b + 4a + 5 = 0
become
a� + (-1)� + 2(-1) + 4a + 5 = 0
a� + 1 - 2 + 4a + 5 = 0
a� + 4a + 4 = 0
(a+2)� = 0
a+2 = 0
a = -2
So since a=-2 and b=-1
mark me has branlist
Similar questions