Question

(a2 + 4ab + 4b2 - 9c2) ÷ (a + 2b + 3c) solve this

Answer 1

Answer:

9c−a2+4ab−4b2. =9c−(a2−4ab+4b2). =9c−(a−2b)2. =(3 ​c)2−(a−2b)2. =[3 ​c+a−2b][3 ​−a+2b].

Step-by-step explanation:

Answer 2

Answer: put a= 0, b= 1 , c =1

then, 0+2*1+3*1=5 , 2*0*1+6*1*1+3*0*1=6

then, a²+(4b)²+9c²= 0+4+9 = 13

13 Answer