a2+4b2-4ab-4c2 factorise it
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Answered by
77
Hi ,
a² + 4b² - 4ab - 4c²
= a² + ( 2b )² - 2 × a × 2b - 4c²
= ( a - 2b )² - ( 2c )²
= [ ( a - 2b ) + 2c ] [ ( a - 2b ) - 2c ]
= ( a - 2b + 2c )( a - 2b - 2c )
I hope this helps you.
: )
a² + 4b² - 4ab - 4c²
= a² + ( 2b )² - 2 × a × 2b - 4c²
= ( a - 2b )² - ( 2c )²
= [ ( a - 2b ) + 2c ] [ ( a - 2b ) - 2c ]
= ( a - 2b + 2c )( a - 2b - 2c )
I hope this helps you.
: )
vineetkumar0909:
too good answer bro
Answered by
6
A²+4b²-4ab-4c² →{a²+(2b)²-2(2b)a}-(2c)² →(a-2b)²-(2c)²{Since, a²+b²-2ab=(a-b)²} →(a-2b-2c)(a-2b+2c){Since, a²-b²=(a+b)(a-b)} (ÆÑẞWĒR)
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