A2-9 has no real zeros do u agree with this or not ?give reason (plz answer this question)
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Answer:
NO
Step-by-step explanation:
a^2 - 9
= a^2 + 0 x - 9
a = 1
b = 0
c = -9
Discriminent = b^2 - 4ac
= 0^2 - 4(-9)(1)
= 36
Discriminent is positive, so the given polynomial have real zeroes .
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