Math, asked by saty50424, 1 year ago

a2+a+1=0 then value of (a2_a+1) (a+1_a2)

Answers

Answered by gsnarayana

1

-a^2=a+1
-a=a^2+1
(a2_a+1) (a+1_a2)
(-a-a)(-a^2-a^2)
(-2a)(-2a^2)
4a^3 is answer

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