Question

a²-a² = ? answer in algebra.



Add the following values (it's algebra )

(a² - ab + 2bc + 3c²) + (2ab + b² - 3bc - 4c²) + (ab - 4bc + c² - a²)
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Answer 1

a²_ab+2bc+3c²,2ab+b²_3bc_4²

Answer 2

Given,

$\[\left( {{a^2} - ab + 2bc + 3{c^2}} \right) + \left( {2ab + {b^2} - 3bc - 4{c^2}} \right) + \left( {ab - 4bc + {c^2} - {a^2}} \right)\]$

Solution,

$\[\begin{array}{l} = \left( {{a^2} - ab + 2bc + 3{c^2}} \right) + \left( {2ab + {b^2} - 3bc - 4{c^2}} \right) + \left( {ab - 4bc + {c^2} - {a^2}} \right)\\ = - ab + 2bc + 2ab + {b^2} - 3bc + ab - 4bc\\ = 2ab + {b^2} - 5bc\end{array}\]$

Hence the solution is $\[2ab + {b^2} - 5bc\]$