Math, asked by afagare09, 4 months ago

a²/a³ × a³/a⁴ ×a⁴/a²​

Answers

Answered by nesroy08
0

Answer:

a²/a³ × a³/a⁴ ×a⁴/a²

=> a ^2-3 x a ^ 3-4 x a ^ 4-2

=> a ^ -1 x a ^ -1 x

=> 1/a x 1/a x a x a

=> 1 x 1 or 1² = 1

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Answered by Anonymous
0

Answer:

1

Step-by-step explanation:

\frac{a^{2} }{a^{3} } × \frac{a^{3} }{a^{4} } × \frac{a^{4} }{a^{2} }

= (a^{2-3} ) × (a^{3-4} ) × (a^{4-2} )

= a^{-1} × a^{-1} × a^{2}

= a^{(-1)+(-1)+2}

= a^{-1-1+2}

= a^{0}

= 1

Hope that helps you...☺

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