Question

a² +ab(1+b)+b² Pls answer it fast​

Answer 1

Answer:

Step-by-step explanation:

a^2+ab+ab^2+b^2=0

a(a+b) +b^2(a+b) =0

(a+b) (a+b^2) =0

a+b=0, a+b^2=0

a=-b, a=-b^2(not possible because square of any number can not be negative)

Hence a=-b

Hope it helps you...

Answer 2

Step-by-step explanation:

a^2+ab+ab^2+b^2=0

a(a+b)+b²(a+b)=0

(a+b)(a+b^2)=0

(a+b)=0

(a+b^2)=0

a=-b & b² not equal to zero

Hence a=-b

Solved by Shot Tricks :

Put a=-1 & b= 1

put in equation

(-1²)+-1×1(1+1)+1²

1-1(2)+1

1-2+1=0

hence we can write a=-b