Question

a2+ab+b2=25
{b^2+bc+c^2=49}b2+bc+c2=49
{c^2+ca+a^2=64}c2+ca+a2=64
Then, find the value of
(a+b+c)²-100 = ????
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Answer 1

Answer:

(a+b+c)

2=a

2+b

2+c

2+2ab+2bc+2ca ⇒(a+b+c)

2=a

2+b2+c2+2(ab+bc+ca)

ab+bc+ca=10,a

2+b2+c2

=16 ⇒(a+b+c)

2=16+2(10)

a+b+c=16+20=6

Step-by-step explanation:

Answer 2

Answer:

Formula,

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca

⇒(a+b+c)2=a2+b2+c2+2(ab+bc+ca)

Given,

ab+bc+ca=10,a2+b2+c2=16

⇒(a+b+c)2=16+2(10)

a+b+c=16+20=6